Chapter 4 notes from the Text Book Section 4.3 Riemann Sums and Definite Integrals |
Definition of Riemann
Sum Let f be defined on the closed interval [a,b], and let Δ
be a partition of [a,b] given by a
= x0 < x1 < x2 < x3
< . . . . < xn-1 < xn = b where Δxί is
the width of the ίth subinterval.
If C ί is any point in the ίth subinterval, the then sum
( when the upper boundary is n and the lower boundary is ί=1) Σ
f(C ί
) Δxί,
xn-1
≤ C ί
≤
xί,
is called a Riemann sum of f for the partition Δ.
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|| Δ
|| = Δx = (b-a) / n
regular partition
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Definition of a
Definite Integral If f is defined on the closed interval [a,b] and the limit lim(|| Δ
|| à
0) Σ
f(C ί
) Δxί
=
∫ a b f(x)
dx The limit is called the
definite integral of f from a to b. The
number a is the lower limit of integration, and the number b is the upper
limit of integration. |
Theorem 4.4
Continuity Implies Integrability If a function f is
continuous on the closed interval [a,b], then f is integrable on the [a,b].
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Theorem 4.5
The Definite Integral as the Area of a Region If f is continuous and nonnegative on the close interval [a,b],
then the area of the region bounded by the graph of f, the x-axis, and the
vertical lines x = a
Area = ∫ a b f(x)
dx |
Example 6
Evaluation of a Definite Integral Evaluate ∫ 1
3 (-x^2 + 4x -3) dx using
each of the fallowing values. ∫ 1 3
(x^2) dx = 26/3, ∫
1 3 (x) dx = 4, ∫ 1 3 dx = 2 Solution ∫ 1 3
(-x^2 + 4x -3) dx =
∫ 1 3 (-x^2) dx
+ ∫ 1 3 (4x ) dx + ∫ 1
3 (-3) dx
= -∫ 1 3 (-x^2) dx
+ 4∫ 1 3 dx
- 3 ∫ 1 3 dx
= -(26/3) + 4(4) -3(2)
=
(4/3)
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