Chapter 4 notes from the Text Book Section 4.2 Area |
Theorem 4.2 Summation Formulas (upper bounds on each is n, lower bounds on each is ί = 1) 1.
Σ c = cn
2. Σ ί = (n*(n
+ 1))/ 2 3. Σ ί ^2 = (n*(n + 1)*(2n+1))/6 4. Σ ί ^3 = (n^2*(n + 1)^2)/4
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Evaluating a sum
( the upper
bounds is n and the lower bounds is ί ) Σ ((ί +1)/n^2) for n = 10, 100, 1000, and 10000. Solution: Applying Theorem 4.2, you can write Σ ((ί +1)/n^2)
= (1/n^2) Σ (ί +1) Factor constant
1/n^2 out of the sum = (1/n^2) (Σ ί +
Σ 1 )
write as two sums = (1/n^2) [((n*(n + 1))/2) + n
]
Apply Theorem 4.2 = (1/n^2) [((n^2) + 3n)/2 ]
Simplify = (n+3)/2n
Simplify **
Now you can evaluate the sum by substitution the appropraite values of n n =
10 à
0.65000, n = 100 à
0.51500, n = 1,000 à
0.50150, n = 10,000 à
0.50015 lim(
nà
∞) ((n+3)/2n) = 1/2
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Theorem 4.3 Limit of the
Lower and Upper Sums Let
f be continous and nonnegative on the interval [a,b]. The limits as ( nà
∞) of both the lower and upper sums exist and are equal to each
other. That is, lim( nà ∞) s(n) = lim( nà ∞) Σ f(m ί) ∆x
=
lim( nà
∞) Σ f(M ί) ∆x = lim( nà ∞) S(n) Where ∆x = (b-a)/n and f(m ί) and f(M ί) are the minimum and the maximum values of f on the subinterval.
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Definition of the Area of a Region in the PlaneLet
f be continous and nonnegative on the interval [a,b]. The area of the region bounded by the graph of f, the x-axis,
and the vertical lines x = a and x = b is Area = lim( nà ∞) Σ f(c ί) ∆x. x ί-1 £ c ί £ x ί where ∆x = (b-a)/n
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